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Draw the graph of the following quadrati...

Draw the graph of the following quadratic functions.
Q. `y=x^(2)-5x+6" "0lexle5`.

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To draw the graph of the quadratic function \( y = x^2 - 5x + 6 \) for the range \( 0 \leq x \leq 5 \), we will follow these steps: ### Step 1: Identify the quadratic function The given quadratic function is: \[ y = x^2 - 5x + 6 \] ### Step 2: Factor the quadratic equation To find the roots (zeros) of the quadratic function, we can factor it: \[ y = (x - 2)(x - 3) \] This gives us the roots: \[ x = 2 \quad \text{and} \quad x = 3 \] ### Step 3: Calculate the value of \( y \) for various \( x \) values We will calculate \( y \) for \( x = 0, 1, 2, 3, 4, 5 \): - For \( x = 0 \): \[ y = 0^2 - 5(0) + 6 = 6 \] Point: \( (0, 6) \) - For \( x = 1 \): \[ y = 1^2 - 5(1) + 6 = 1 - 5 + 6 = 2 \] Point: \( (1, 2) \) - For \( x = 2 \): \[ y = 2^2 - 5(2) + 6 = 4 - 10 + 6 = 0 \] Point: \( (2, 0) \) - For \( x = 3 \): \[ y = 3^2 - 5(3) + 6 = 9 - 15 + 6 = 0 \] Point: \( (3, 0) \) - For \( x = 4 \): \[ y = 4^2 - 5(4) + 6 = 16 - 20 + 6 = 2 \] Point: \( (4, 2) \) - For \( x = 5 \): \[ y = 5^2 - 5(5) + 6 = 25 - 25 + 6 = 6 \] Point: \( (5, 6) \) ### Step 4: List the points Now, we have the following points to plot: - \( (0, 6) \) - \( (1, 2) \) - \( (2, 0) \) - \( (3, 0) \) - \( (4, 2) \) - \( (5, 6) \) ### Step 5: Plot the points on a graph On a Cartesian coordinate system: - Mark the x-axis from 0 to 5. - Mark the y-axis from 0 to 6. - Plot the points calculated above. ### Step 6: Draw the parabola Connect the points smoothly to form a parabolic curve. The parabola opens upwards, and it intersects the x-axis at \( (2, 0) \) and \( (3, 0) \). ### Step 7: Identify the vertex The vertex of the parabola can be found using the formula: \[ x = -\frac{b}{2a} = -\frac{-5}{2 \cdot 1} = \frac{5}{2} = 2.5 \] Substituting \( x = 2.5 \) into the function to find \( y \): \[ y = (2.5)^2 - 5(2.5) + 6 = 6.25 - 12.5 + 6 = -0.25 \] Thus, the vertex is at \( (2.5, -0.25) \).
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