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If m= ""^(n) C(2), then ""^(m) C(2) is e...

If `m= ""^(n) C_(2),` then `""^(m) C_(2)` is equal to

A

`3.""^(n) C_(4)`

B

`""^(n+1)C_4`

C

`3.""^(n+1)C_4`

D

`3.""^(n+1)C_3`

Text Solution

Verified by Experts

The correct Answer is:
C
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