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If the coefficients of x^2 and x^3 in th...

If the coefficients of `x^2 and x^3` in the expansion of `(3 + ax)^(9)` be same, then the value of `a` is

A

(a) `(3)/(7)`

B

(b) `(7)/(3)`

C

(c) `(7)/(9)`

D

(d) `(9)/(7)`

Text Solution

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The correct Answer is:
To find the value of \( a \) such that the coefficients of \( x^2 \) and \( x^3 \) in the expansion of \( (3 + ax)^9 \) are equal, we can follow these steps: ### Step 1: Identify the General Term The general term in the binomial expansion of \( (a + b)^n \) is given by: \[ T_{r+1} = \binom{n}{r} a^{n-r} b^r \] In our case, \( a = 3 \), \( b = ax \), and \( n = 9 \). Thus, the general term becomes: \[ T_{r+1} = \binom{9}{r} (3)^{9-r} (ax)^r = \binom{9}{r} 3^{9-r} a^r x^r \] ### Step 2: Find the Coefficient of \( x^2 \) To find the coefficient of \( x^2 \), we set \( r = 2 \): \[ T_{3} = \binom{9}{2} 3^{9-2} a^2 x^2 \] The coefficient of \( x^2 \) is: \[ \text{Coefficient of } x^2 = \binom{9}{2} 3^7 a^2 \] ### Step 3: Find the Coefficient of \( x^3 \) To find the coefficient of \( x^3 \), we set \( r = 3 \): \[ T_{4} = \binom{9}{3} 3^{9-3} a^3 x^3 \] The coefficient of \( x^3 \) is: \[ \text{Coefficient of } x^3 = \binom{9}{3} 3^6 a^3 \] ### Step 4: Set the Coefficients Equal According to the problem, the coefficients of \( x^2 \) and \( x^3 \) are equal: \[ \binom{9}{2} 3^7 a^2 = \binom{9}{3} 3^6 a^3 \] ### Step 5: Simplify the Equation We can simplify this equation by dividing both sides by \( 3^6 \): \[ \binom{9}{2} 3 a^2 = \binom{9}{3} a^3 \] Next, we can express \( \binom{9}{2} \) and \( \binom{9}{3} \): \[ \binom{9}{2} = \frac{9 \times 8}{2 \times 1} = 36 \] \[ \binom{9}{3} = \frac{9 \times 8 \times 7}{3 \times 2 \times 1} = 84 \] Substituting these values in: \[ 36 \times 3 a^2 = 84 a^3 \] This simplifies to: \[ 108 a^2 = 84 a^3 \] ### Step 6: Rearranging the Equation Rearranging gives: \[ 84 a^3 - 108 a^2 = 0 \] Factoring out \( a^2 \): \[ a^2 (84 a - 108) = 0 \] This gives us two cases: 1. \( a^2 = 0 \) (which implies \( a = 0 \), but we discard this as it does not satisfy the original problem) 2. \( 84 a - 108 = 0 \) ### Step 7: Solve for \( a \) Solving \( 84 a - 108 = 0 \): \[ 84 a = 108 \implies a = \frac{108}{84} = \frac{9}{7} \] ### Conclusion Thus, the value of \( a \) is: \[ \boxed{\frac{9}{7}} \]
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