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Find the slope of a line perpendicular to the line which passes through each pair of the following points: \[{\text{(}}{{\text{x}}_1}{\text{,}}{{\text{y}}_1}{\text{) and (}}{{\text{x}}_2}{\text{,}}{{\text{y}}_2}{\text{)}}{\text{.}}\]

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To find the slope of a line that is perpendicular to the line passing through the points \((x_1, y_1)\) and \((x_2, y_2)\), we can follow these steps: ### Step 1: Calculate the slope of the line through the given points The slope \(m_1\) of the line passing through the points \((x_1, y_1)\) and \((x_2, y_2)\) is given by the formula: \[ m_1 = \frac{y_2 - y_1}{x_2 - x_1} \] ### Step 2: Use the property of perpendicular lines For two lines to be perpendicular, the product of their slopes must equal \(-1\). If \(m_2\) is the slope of the line perpendicular to the line with slope \(m_1\), then: \[ m_1 \cdot m_2 = -1 \] ### Step 3: Solve for the slope of the perpendicular line From the equation \(m_1 \cdot m_2 = -1\), we can express \(m_2\) in terms of \(m_1\): \[ m_2 = -\frac{1}{m_1} \] Substituting the expression for \(m_1\) from Step 1: \[ m_2 = -\frac{1}{\frac{y_2 - y_1}{x_2 - x_1}} = -\frac{x_2 - x_1}{y_2 - y_1} \] ### Final Result Thus, the slope of the line that is perpendicular to the line passing through the points \((x_1, y_1)\) and \((x_2, y_2)\) is: \[ m_2 = \frac{x_1 - x_2}{y_2 - y_1} \]
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ICSE-THE STRAIGHT LINE -EXERCISE 16 (a)
  1. Find the slope of a line perpendicular to the line whose slope is ...

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  2. Find the slope of a line perpendicular to the line whose slope is 5.

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  3. Find the slope of a line perpendicular to the line whose slope is -5...

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  4. Find the slope of a line perpendicular to the line whose slope is 0

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  5. Find the slope of a line perpendicular to the line whose slope is I...

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  6. Find the slope of a line perpendicular to the line which passes throug...

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  7. Find the slope of a line perpendicular to the line which passes throug...

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  8. Find the slope of a line perpendicular to the line which passes throug...

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  9. Find the slope of a line perpendicular to the line which passes throug...

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  10. In rectangle ABCD, slope of AB=5/(6). State the slope of BC .

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  11. In rectangle ABCD, slope of AB=5/(6). State the slope of CD

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  12. In rect. ABCD, slope of AB=5/(6). State the slope of DA

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  13. In parallelogram ABCD, slope of AB = -2, slope of BC = 3/(5). State th...

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  14. In parallelogram ABCD, slope of AB = -2, slope of BC = 3/(5). State th...

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  15. In parallelogram ABCD, slope of AB = -2, slope of BC = 3/(5). State th...

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  16. In parallelogram ABCD, slope of AB = -2, slope of BC = 3/(5). State th...

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  17. The vertices of a DeltaABC are A(1, 1), B(7, 3) and C(3, 6). State the...

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  18. The vertices of a DeltaABC are A(1, 1), B(7, 3) and C(3, 6). State the...

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  19. The vertices of a DeltaABC are A(1, 1), B(7, 3) and C(3, 6). State the...

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  20. The line joining (-5, 7) and (0, -2) is perpendicular to the line join...

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