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Find the equation of the ellipse with ...

Find the equation of the ellipse with
focus at (0, 0), eccentricity is `5/6`, and directrix is `3x+4y-1=0`.

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To find the equation of the ellipse with the given parameters, we will follow these steps: ### Step 1: Understand the parameters We are given: - Focus (S) at (0, 0) - Eccentricity (e) = 5/6 - Directrix: 3x + 4y - 1 = 0 ### Step 2: Write the formula for the ellipse The definition of an ellipse states that for any point P(x, y) on the ellipse, the ratio of the distance from the focus to the distance from the directrix is equal to the eccentricity (e). This can be expressed as: \[ \frac{PS}{PM} = e \] where PS is the distance from the point P to the focus S, and PM is the distance from the point P to the directrix. ### Step 3: Calculate PS The distance PS from point P(x, y) to the focus (0, 0) is given by: \[ PS = \sqrt{x^2 + y^2} \] ### Step 4: Calculate PM The distance PM from point P(x, y) to the directrix can be calculated using the formula for the distance from a point to a line. The directrix can be expressed in the form Ax + By + C = 0, where A = 3, B = 4, and C = -1. The distance PM is given by: \[ PM = \frac{|3x + 4y - 1|}{\sqrt{3^2 + 4^2}} = \frac{|3x + 4y - 1|}{5} \] ### Step 5: Set up the equation From the definition of the ellipse, we have: \[ \frac{\sqrt{x^2 + y^2}}{\frac{|3x + 4y - 1|}{5}} = \frac{5}{6} \] Cross-multiplying gives: \[ 6\sqrt{x^2 + y^2} = 5 \cdot \frac{|3x + 4y - 1|}{5} \] This simplifies to: \[ 6\sqrt{x^2 + y^2} = |3x + 4y - 1| \] ### Step 6: Square both sides To eliminate the square root, we square both sides: \[ 36(x^2 + y^2) = (3x + 4y - 1)^2 \] ### Step 7: Expand the right-hand side Expanding the right-hand side: \[ (3x + 4y - 1)^2 = 9x^2 + 24xy + 16y^2 - 6x - 8y + 1 \] ### Step 8: Set the equation Now we have: \[ 36(x^2 + y^2) = 9x^2 + 24xy + 16y^2 - 6x - 8y + 1 \] Rearranging gives: \[ 36x^2 + 36y^2 - 9x^2 - 16y^2 - 24xy + 6x + 8y - 1 = 0 \] This simplifies to: \[ 27x^2 + 20y^2 - 24xy + 6x + 8y - 1 = 0 \] ### Final Equation Thus, the equation of the ellipse is: \[ 27x^2 + 20y^2 - 24xy + 6x + 8y - 1 = 0 \] ---
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ICSE-ELLIPSE-EXERCISE 24
  1. Find the equation of the ellipse with its centre at (3, 1), vertex at ...

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  2. Find the equation of the ellipse whose centre is at (0, 2) and major a...

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  3. Find the equation of the ellipse with focus at (1, -1), directrix x ...

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  4. Find the equation of the ellipse with focus at (0, 0), eccentricity ...

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  5. Find the equation of the ellipse from the following data: axis is coin...

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  6. A point P(x, y) moves so that the product of the slopes of the two lin...

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  7. Find the eccentricity, the coordinates of the foci, and the length of ...

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  8. For the ellipse, 9x^(2)+16y^(2)=576, find the semi-major axis, the sem...

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  9. Find the length of the axes, the co-ordinates of the foci, the eccentr...

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  10. Find the eccentricity of the ellipse, 4x^(2)+9y^(2)-8x-36y+4=0.

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  11. Find the centre of the ellipse, (x^(2)-ax)/a^(2)+(y^(2)-by)/b^(2)=0.

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  12. Find the distance between a focus and an extremity of the minor axis o...

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  13. Given the ellipse 36x^(2)+100y^(2)=3600, find the equations and the le...

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  14. The focal distance of an end of the minor axis of the ellipse is k and...

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  15. Find the eccentricity of the ellipse whose latus rectum is 4 and dista...

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  16. The directrix of a conic section is the line 3x+4y=1 and the focus S i...

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  17. Find the equation to the conic section whose focus is (1, -1), eccentr...

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  18. Find the equation of the ellipse whose foci are (-1, 5) and (5, 5) and...

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  19. Find the ellipse if its foci are (pm2, 0) and the length of the latus ...

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  20. Find the eccentricity of the ellipse of minor axis is 2b, if the line ...

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