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The directrix of a conic section is the ...

The directrix of a conic section is the line `3x+4y=1` and the focus S is (-2, 3). If the eccentricity e is `1/sqrt(2)`, find the equation to the conic section.

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To find the equation of the conic section given the directrix, focus, and eccentricity, we can follow these steps: ### Step 1: Identify the given information - Directrix: \(3x + 4y = 1\) - Focus \(S\): \((-2, 3)\) - Eccentricity \(e\): \(\frac{1}{\sqrt{2}}\) ### Step 2: Set up the point \(P\) on the conic Let \(P\) be a point on the conic with coordinates \((x, y)\). The distance from the focus \(S\) to point \(P\) is denoted as \(SP\), and the distance from point \(P\) to the directrix is denoted as \(Pm\). ### Step 3: Use the definition of eccentricity According to the definition of eccentricity for a conic section: \[ \frac{SP}{Pm} = e \] This can be rearranged to: \[ SP = e \cdot Pm \] ### Step 4: Calculate \(SP\) Using the distance formula, the distance \(SP\) from the focus \(S(-2, 3)\) to point \(P(x, y)\) is: \[ SP = \sqrt{(x + 2)^2 + (y - 3)^2} \] ### Step 5: Calculate \(Pm\) The distance \(Pm\) from point \(P(x, y)\) to the directrix \(3x + 4y - 1 = 0\) can be calculated using the formula for the distance from a point to a line: \[ Pm = \frac{|3x + 4y - 1|}{\sqrt{3^2 + 4^2}} = \frac{|3x + 4y - 1|}{5} \] ### Step 6: Substitute into the eccentricity equation Substituting \(SP\) and \(Pm\) into the eccentricity equation gives: \[ \sqrt{(x + 2)^2 + (y - 3)^2} = \frac{1}{\sqrt{2}} \cdot \frac{|3x + 4y - 1|}{5} \] ### Step 7: Square both sides to eliminate the square root Squaring both sides results in: \[ (x + 2)^2 + (y - 3)^2 = \frac{1}{2} \cdot \left(\frac{|3x + 4y - 1|}{5}\right)^2 \] This simplifies to: \[ (x + 2)^2 + (y - 3)^2 = \frac{(3x + 4y - 1)^2}{50} \] ### Step 8: Expand both sides Expanding the left side: \[ (x^2 + 4x + 4) + (y^2 - 6y + 9) = x^2 + y^2 + 4x - 6y + 13 \] Expanding the right side: \[ \frac{(3x + 4y - 1)^2}{50} = \frac{9x^2 + 24xy + 16y^2 - 6x - 8y - 2}{50} \] ### Step 9: Multiply through by 50 to eliminate the fraction Multiplying both sides by 50 gives: \[ 50(x^2 + y^2 + 4x - 6y + 13) = 9x^2 + 24xy + 16y^2 - 6x - 8y - 2 \] ### Step 10: Rearrange and simplify Rearranging the equation leads to: \[ 41x^2 + 34y^2 + 206x - 292y + 199 = 0 \] ### Final Equation Thus, the equation of the conic section is: \[ 41x^2 + 34y^2 + 206x - 292y + 199 = 0 \]
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ICSE-ELLIPSE-EXERCISE 24
  1. Find the equation of the ellipse with its centre at (3, 1), vertex at ...

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  2. Find the equation of the ellipse whose centre is at (0, 2) and major a...

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  3. Find the equation of the ellipse with focus at (1, -1), directrix x ...

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  4. Find the equation of the ellipse with focus at (0, 0), eccentricity ...

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  5. Find the equation of the ellipse from the following data: axis is coin...

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  6. A point P(x, y) moves so that the product of the slopes of the two lin...

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  7. Find the eccentricity, the coordinates of the foci, and the length of ...

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  8. For the ellipse, 9x^(2)+16y^(2)=576, find the semi-major axis, the sem...

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  9. Find the length of the axes, the co-ordinates of the foci, the eccentr...

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  10. Find the eccentricity of the ellipse, 4x^(2)+9y^(2)-8x-36y+4=0.

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  11. Find the centre of the ellipse, (x^(2)-ax)/a^(2)+(y^(2)-by)/b^(2)=0.

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  12. Find the distance between a focus and an extremity of the minor axis o...

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  13. Given the ellipse 36x^(2)+100y^(2)=3600, find the equations and the le...

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  14. The focal distance of an end of the minor axis of the ellipse is k and...

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  15. Find the eccentricity of the ellipse whose latus rectum is 4 and dista...

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  16. The directrix of a conic section is the line 3x+4y=1 and the focus S i...

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  17. Find the equation to the conic section whose focus is (1, -1), eccentr...

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  18. Find the equation of the ellipse whose foci are (-1, 5) and (5, 5) and...

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  19. Find the ellipse if its foci are (pm2, 0) and the length of the latus ...

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  20. Find the eccentricity of the ellipse of minor axis is 2b, if the line ...

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