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Derive the equation of the locur of a po...

Derive the equation of the locur of a point equidistant from the points `(1, -2, 3) and (-3,4,2).`

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The correct Answer is:
`8x - 12 y + 2z + 15 =0`
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ICSE-POINTS AND THEIR COORDINATES -EXERCISE 26 (A)
  1. Find the distance from the origin to each of the point: (2,2,3)

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  2. Find the distance from the origin to each of the point: (4, -1, 2)

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  3. Find the distance from the origin to each of the point: (0, 4,-4)

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  4. Find the distance from the origin to each of the point: (-4,-3,-2)

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  5. Find the distance between each of pair of point: (2,5,3 and (-3,2,1)...

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  6. Find the distance between each of pair of point: (0,3,0) and (6,0,2)

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  7. Find the distance between each of pair of point: (-4,-2,0) and (3,3,...

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  8. Show that the triangle with vetices (6,10,10) , (1,0, -5), (6, -10, 0)...

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  9. Show that the triangle with vertices A (3,5,-4), B (-1, 1,2) C (-5,-5,...

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  10. Show that (4,2,4) , (10, 2, -2) and (2, 0, -4) are the vertices of an ...

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  11. Show that the point A (1,-1,3), B ( 2,-4,5) and C ( 5,-13,11) are col...

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  12. Derive the equation of the locur of a point equidistant from the point...

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  13. Derive the equation of the locus of a point twice as far from (-2,3,4)...

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  14. Find the equation of the locus of a point whose distance from the y-ax...

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  15. Find the equation of the locus of point whose distance from the xy-pla...

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  16. A point moves so that the differerence of the squares of its distance ...

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  17. Find the equation of the locus of a point whose distanace from the z-a...

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