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The three points A (0,0,0), B (2,-3, 3),...

The three points A (0,0,0), B (2,-3, 3), C(-2,3,-3) are collinear. Find in what ratio each point divides the segment joining the other two.

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To find the ratio in which each point divides the segment joining the other two points, we will follow these steps: ### Step 1: Identify the Points The given points are: - A(0, 0, 0) - B(2, -3, 3) - C(-2, 3, -3) ### Step 2: Calculate the Distances We will calculate the distances between the points A, B, and C using the distance formula in 3D space, which is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \] #### Distance AB Using points A(0, 0, 0) and B(2, -3, 3): \[ AB = \sqrt{(2 - 0)^2 + (-3 - 0)^2 + (3 - 0)^2} = \sqrt{2^2 + (-3)^2 + 3^2} = \sqrt{4 + 9 + 9} = \sqrt{22} \] #### Distance BC Using points B(2, -3, 3) and C(-2, 3, -3): \[ BC = \sqrt{(-2 - 2)^2 + (3 - (-3))^2 + (-3 - 3)^2} = \sqrt{(-4)^2 + (6)^2 + (-6)^2} = \sqrt{16 + 36 + 36} = \sqrt{88} \] #### Distance AC Using points A(0, 0, 0) and C(-2, 3, -3): \[ AC = \sqrt{(-2 - 0)^2 + (3 - 0)^2 + (-3 - 0)^2} = \sqrt{(-2)^2 + (3)^2 + (-3)^2} = \sqrt{4 + 9 + 9} = \sqrt{22} \] ### Step 3: Determine the Ratios Now, we will find the ratio in which point A divides segment BC. We will use the section formula. Let the ratio be \( m:n \). Using the section formula in 3D: \[ x = \frac{mx_2 + nx_1}{m+n}, \quad y = \frac{my_2 + ny_1}{m+n}, \quad z = \frac{mz_2 + nz_1}{m+n} \] For point A(0, 0, 0) dividing segment BC: - \( x_1 = -2, y_1 = 3, z_1 = -3 \) (coordinates of C) - \( x_2 = 2, y_2 = -3, z_2 = 3 \) (coordinates of B) Setting up the equations for x, y, and z coordinates: 1. For x-coordinate: \[ 0 = \frac{m(2) + n(-2)}{m+n} \implies 0 = 2m - 2n \implies m = n \] 2. For y-coordinate: \[ 0 = \frac{m(-3) + n(3)}{m+n} \implies 0 = -3m + 3n \implies m = n \] 3. For z-coordinate: \[ 0 = \frac{m(3) + n(-3)}{m+n} \implies 0 = 3m - 3n \implies m = n \] ### Conclusion From all three coordinates, we find that \( m = n \). Therefore, the ratio in which point A divides segment BC is: \[ \text{Ratio} = 1:1 \]
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