Add the product of `(-13)` and `(-17)` to the quotient of `(-187)` and 11.

Answer

To solve the problem of adding the product of `(-13)` and `(-17)` to the quotient of `(-187)` and `11`, we can follow these steps:

### Step 1: Find the Product of `(-13)` and `(-17)`

To find the product, we multiply the two numbers:

\[ (-13) \times (-17) = 13 \times 17 \]

Calculating \(13 \times 17\):

\[ 13 \times 17 = 221 \]

Since the product of two negative numbers is positive, we have:

\[ (-13) \times (-17) = 221 \]

### Step 2: Find the Quotient of `(-187)` and `11`

Next, we need to divide `(-187)` by `11`:

\[ \frac{-187}{11} \]

Performing the division:

- \(11\) goes into \(18\) one time (1), leaving a remainder of \(7\).
- Bringing down the \(7\) gives us \(77\).
- \(11\) goes into \(77\) seven times (7), with no remainder.

Thus, we have:

\[ \frac{-187}{11} = -17 \]

### Step 3: Add the Product and the Quotient

Now, we add the results from Step 1 and Step 2:

\[ 221 + (-17) = 221 - 17 \]

Calculating this gives:

\[ 221 - 17 = 204 \]

### Final Answer

The final answer is:

\[ \text{Result} = 204 \]

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