Find the additive inverse of:
(i) `6/11`, (ii) `-11/8`

Answer

To find the additive inverse of a rational number, we need to remember that the additive inverse of a number \( a \) is \( -a \). This means that when we add a number and its additive inverse, the result is always zero.

Let's solve the given question step by step:

### Step 1: Find the additive inverse of \( \frac{6}{11} \)

1. Identify the number: \( \frac{6}{11} \).
2. Apply the formula for the additive inverse:
\[ \text{Additive Inverse} = -\left(\frac{6}{11}\right) \]
3. Therefore, the additive inverse of \( \frac{6}{11} \) is:
\[ -\frac{6}{11} \]

### Step 2: Find the additive inverse of \( -\frac{11}{8} \)

1. Identify the number: \( -\frac{11}{8} \).
2. Apply the formula for the additive inverse:
\[ \text{Additive Inverse} = -\left(-\frac{11}{8}\right) \]
3. Since the negative of a negative number is positive, we have:
\[ -\left(-\frac{11}{8}\right) = \frac{11}{8} \]
4. Therefore, the additive inverse of \( -\frac{11}{8} \) is:
\[ \frac{11}{8} \]

### Final Answers:
- The additive inverse of \( \frac{6}{11} \) is \( -\frac{6}{11} \).
- The additive inverse of \( -\frac{11}{8} \) is \( \frac{11}{8} \).

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