Subtract: (i) `3/5` from `7/10`, (ii) `-3/5` from `-5/6`
Text Solution
AI Generated Solution
The correct Answer is:
Let's solve the question step by step.
### Question:
Subtract:
(i) \( \frac{3}{5} \) from \( \frac{7}{10} \)
(ii) \( -\frac{3}{5} \) from \( -\frac{5}{6} \)
### Solution:
#### Part (i): Subtract \( \frac{3}{5} \) from \( \frac{7}{10} \)
1. **Identify the fractions**: We need to subtract \( \frac{3}{5} \) from \( \frac{7}{10} \), which can be written as:
\[
\frac{7}{10} - \frac{3}{5}
\]
2. **Find a common denominator**: The denominators are 10 and 5. The least common multiple (LCM) of 10 and 5 is 10.
3. **Convert the fractions**: Since \( \frac{3}{5} \) needs to be expressed with a denominator of 10:
\[
\frac{3}{5} = \frac{3 \times 2}{5 \times 2} = \frac{6}{10}
\]
4. **Subtract the fractions**:
\[
\frac{7}{10} - \frac{6}{10} = \frac{7 - 6}{10} = \frac{1}{10}
\]
5. **Final answer for part (i)**:
\[
\frac{1}{10}
\]
---
#### Part (ii): Subtract \( -\frac{3}{5} \) from \( -\frac{5}{6} \)
1. **Identify the fractions**: We need to subtract \( -\frac{3}{5} \) from \( -\frac{5}{6} \), which can be written as:
\[
-\frac{5}{6} - \left(-\frac{3}{5}\right)
\]
This simplifies to:
\[
-\frac{5}{6} + \frac{3}{5}
\]
2. **Find a common denominator**: The denominators are 6 and 5. The LCM of 6 and 5 is 30.
3. **Convert the fractions**:
- For \( -\frac{5}{6} \):
\[
-\frac{5}{6} = -\frac{5 \times 5}{6 \times 5} = -\frac{25}{30}
\]
- For \( \frac{3}{5} \):
\[
\frac{3}{5} = \frac{3 \times 6}{5 \times 6} = \frac{18}{30}
\]
4. **Add the fractions**:
\[
-\frac{25}{30} + \frac{18}{30} = \frac{-25 + 18}{30} = \frac{-7}{30}
\]
5. **Final answer for part (ii)**:
\[
-\frac{7}{30}
\]
### Summary of Answers:
(i) \( \frac{1}{10} \)
(ii) \( -\frac{7}{30} \)
---
Topper's Solved these Questions
RATIONAL NUMBERS
ICSE|Exercise EXERCISE 2A |19 Videos
RATIONAL NUMBERS
ICSE|Exercise EXERCISE 2B|4 Videos
RATIO AND PROPORTION
ICSE|Exercise Challenge |1 Videos
REPRESENTING 3 - D IN 2- D
ICSE|Exercise EXERCISE 20 B |1 Videos
Similar Questions
Explore conceptually related problems
Subtract (-3)/5 from 9/(10)dot
Subtract (-3)/5 from 9/(10)dot
Subtract (-3)/8 from (-5)/7
Subtract (-3)/8 from (-5)/7
Subtact: (i) 3/5 from 1/2 , (ii) -4/7 from 2/3 , (iii) -5/6 from -3/4 , (iv) -7/9 from 0, (v) 4 from -6/11 , (vi) 3/8 from -5/6
Subtract 3/4 from 5/6dot
Subtract 3/4 from 5/6.
Subtract: 2a-b from 3a-5b
Subtract: (i) 5x from 9x (ii) -7x from 5x (iii) -8a from -3a
Subtract: (i) 4 from 9 (ii) -4 from 7 (iii) 3 from -8 (iv) -9 from -5
ICSE-RATIONAL NUMBERS -REVISION EXERCISE (FILL IN THE BOXES).