Two coins are tossed simultaneously 100 times. We obtained : Two Heads : 23 times, One Head: 56 times, Zero Head : 21 times. When two coins are tossed at random, what is the probability of getting:
(i) Two Heads?
(ii) One Head?
(iii) Zero Head?

Answer

To solve the problem, we need to find the probabilities of getting two heads, one head, and zero heads when two coins are tossed simultaneously 100 times.

### Step-by-Step Solution:

1. **Identify the total number of trials:**
We are given that two coins are tossed 100 times. Therefore, the total number of trials (outcomes) is:
\[ \text{Total Outcomes} = 100 \]

2. **Calculate the probability of getting two heads:**
We know that two heads were obtained 23 times. The probability of getting two heads (P(Two Heads)) is calculated by dividing the number of times two heads occurred by the total number of trials:
\[ P(\text{Two Heads}) = \frac{\text{Number of times Two Heads occurred}}{\text{Total Outcomes}} = \frac{23}{100} = 0.23 \]

3. **Calculate the probability of getting one head:**
One head was obtained 56 times. The probability of getting one head (P(One Head)) is calculated similarly:
\[ P(\text{One Head}) = \frac{\text{Number of times One Head occurred}}{\text{Total Outcomes}} = \frac{56}{100} = 0.56 \]

4. **Calculate the probability of getting zero heads:**
Zero heads were obtained 21 times. The probability of getting zero heads (P(Zero Heads)) is calculated as follows:
\[ P(\text{Zero Heads}) = \frac{\text{Number of times Zero Heads occurred}}{\text{Total Outcomes}} = \frac{21}{100} = 0.21 \]

### Final Answers:
- Probability of getting Two Heads: **0.23**
- Probability of getting One Head: **0.56**
- Probability of getting Zero Heads: **0.21**