A point charge q is moving with speed v perpendicular to magnetic field B as shown in figure. Explain what should be the magnitude and direction of the applied electric filed so that the net force acting on the charge is zero.

A conductor of length l is moved perpendicular to uniform magnetic field B with velocity v as shown in the figure The e.m.f. induced across the length of the conductor is

Fill ups ……………acts on the charge moving along the direction of magnetic field.

Lorentz Force: If a charge +q is moving in an electric field E, it experiences a force qE called Lorentz electric force.If the charge q is moving in a magnetic field vecB , it experiences a force (vecvxxvecB) called Lorentz magnetic force. If charge q is moving in a n electric field E as well as in magnetic field vecB simultaneously, the total force experience by the charge is the sum of these two forces and is called total Lorentz force. If the charge is q is moving perpendicular to the magnetic field B, the work done by the magnetic field is

If a particle of charge q is moving with velocity v along x-axis and the magnetic field B is acting along Y-axis, use the expression vecF=q(vecv xx vecB) to find the direction of force vecF acting on it.

Five charges, q each, are placed at the corners of a regular pentagon of side a as shown in the figure. What will be the electric field at O, the centre of the pentagon? What will be the electric field at O, fi the charge from one of the corners (Say A) is removed? What will be the electric field at O, if the charge q at A is repalced by - q?

A charged particle is moving away from you. If the direction of the magnetic field is clockwise, what is the charge on the particle?

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . When a charged particle q is moving with velocity vecv in a magnetic field vecB , the force is non-zero. It means.