Why does a convex lens of glass `mu=1.5` behave as a diverging lens when immersed in carbon disulphide of higher refractive index `mu=1.65`?

A double convex lens has radii 20 cm.The refractive index of glass is 1.5.Compure the focal length of this lens in air and when immersed in carbon disulphide of refractive index = 1.63.

Focal length of a convex lens of refractive index 1.5 is 2 cm.Focal length of lens,when immersed in a liquid of refractive index of 1.25 will be

What happens when a convex lens of refractive index 1.2 is immersed in a liquid of refractive index 1.3?

A concave lens made of a material of refractive index mu_g is immersed in a medium of refractive index mu_l , equal to and

A glass of refractive index 1.45 disappears when immersed in a liquid. What is the value of refractive index of the light?

The radii of curvature of a convex lens are 20 cm and 30 cm nd the refractive index of its material is 1.5 .How its nature nd focal length will change ,when it is immersed in a liquid of refractive index = 1.6?

A lens is made of flint glass(refractive index=1.5).When the lens is immersed in a liquid of refractive index 1.25 ,the focal length

Explain what happens ,when a convex lens of refractive index 1.2 is immersed in a liquid of refractive index 1.3.