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7cosectheta+24sectheta=25cosecthetasecth...

`7cosectheta+24sectheta=25cosecthetasectheta`, then `costheta=?`

A

`(5)/(24)`

B

`(7)/(24)`

C

`(11)/(24)`

D

`(13)/(24)`

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The correct Answer is:
To solve the equation \( 7 \csc \theta + 24 \sec \theta = 25 \csc \theta \sec \theta \) and find the value of \( \cos \theta \), we can follow these steps: ### Step 1: Rewrite the equation using trigonometric identities We know that: - \( \csc \theta = \frac{1}{\sin \theta} \) - \( \sec \theta = \frac{1}{\cos \theta} \) Substituting these into the equation gives us: \[ 7 \left(\frac{1}{\sin \theta}\right) + 24 \left(\frac{1}{\cos \theta}\right) = 25 \left(\frac{1}{\sin \theta}\right) \left(\frac{1}{\cos \theta}\right) \] ### Step 2: Clear the fractions To eliminate the fractions, multiply through by \( \sin \theta \cos \theta \): \[ 7 \cos \theta + 24 \sin \theta = 25 \] ### Step 3: Rearrange the equation Rearranging gives: \[ 7 \cos \theta + 24 \sin \theta - 25 = 0 \] ### Step 4: Isolate one of the trigonometric functions We can express \( \sin \theta \) in terms of \( \cos \theta \): \[ 24 \sin \theta = 25 - 7 \cos \theta \] \[ \sin \theta = \frac{25 - 7 \cos \theta}{24} \] ### Step 5: Use the Pythagorean identity Using the identity \( \sin^2 \theta + \cos^2 \theta = 1 \): \[ \left(\frac{25 - 7 \cos \theta}{24}\right)^2 + \cos^2 \theta = 1 \] ### Step 6: Expand and simplify Expanding the left side: \[ \frac{(25 - 7 \cos \theta)^2}{576} + \cos^2 \theta = 1 \] Multiply through by 576 to eliminate the fraction: \[ (25 - 7 \cos \theta)^2 + 576 \cos^2 \theta = 576 \] ### Step 7: Expand the squared term Expanding \( (25 - 7 \cos \theta)^2 \): \[ 625 - 350 \cos \theta + 49 \cos^2 \theta + 576 \cos^2 \theta = 576 \] Combine like terms: \[ 625 - 350 \cos \theta + 625 \cos^2 \theta = 576 \] ### Step 8: Rearrange to form a quadratic equation Rearranging gives: \[ 625 \cos^2 \theta - 350 \cos \theta + 49 = 0 \] ### Step 9: Use the quadratic formula Using the quadratic formula \( \cos \theta = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \): Here, \( a = 625, b = -350, c = 49 \): \[ \cos \theta = \frac{350 \pm \sqrt{(-350)^2 - 4 \cdot 625 \cdot 49}}{2 \cdot 625} \] Calculate the discriminant: \[ \sqrt{122500 - 122500} = 0 \] Thus: \[ \cos \theta = \frac{350}{1250} = \frac{7}{25} \] ### Final Answer \[ \cos \theta = \frac{7}{25} \] ---
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ADVANCED MATHS BY ABHINAY MATHS ENGLISH-TRIGONOMETRY -EXERCISES (Multiple Choice Questions)
  1. If (sec^(4)alpha)/(sec^(2)beta)-(tan^(4)alpha)/(tan^(2)beta)=1 where a...

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  2. If (cos^(4)alpha)/(cos^(2)beta)+(sin^(4)alpha)/(sin^(2)beta)=1 then (c...

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  3. 7cosectheta+24sectheta=25cosecthetasectheta, then costheta=?

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  4. If 8sectheta+6cosectheta=20, then cottheta=?

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  5. The numerical value of cos 2pi/7 + cos 4pi/7 + cos 6pi/7 is=........

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  6. cos15^(@)cos7""(1)/(2)""^(@).cos82""(1)/(2)""^(@)=?

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  7. tan^(2)theta=1-e^(2), then sectheta+tan^(3)theta.cosectheta=?

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  8. 3tanthetatanphi=1, then (cos(theta-phi))/(cos(theta+phi))=?

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  9. tan20^(@)+tan40^(@)+sqrt(3)tan20^(@).tan40^(@)=?

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  10. sin36^(@).sin72^(@).sin108^(@).sin144^(@)=?

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  11. (2cos40^(@)-cos20^(@))/(sin20^(@))=?

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  12. The point (4,3) is translated to the point (3,1) and then the axes ar...

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  13. (cosx)/(cosy)=n,(sinx)/(siny)=m, then (m^(2)-n^(2))sin^(2)y=?

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  14. If xcostheta+ysintheta=4&xcostheta-ysintheta=0, then which one is corr...

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  15. If tan^(2)theta+cot^(2)theta=14, then sectheta.cosectheta=?

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  16. If cos(alpha+beta)=(4)/(5) and sin(alpha-beta)=(5)/(13) , where alpha ...

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  17. If tantheta-tanphi=xandcotphi-cottheta=y, then cot(theta-phi)=?

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  18. If 3costheta=5sintheta, then ((5sintheta-2sec^(3)theta+2costheta)/(5si...

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  19. sectheta+tantheta=2+sqrt(5), then sintheta will be

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  20. If 3tantheta+4=0 where (pi)/(2)lt thetaltpi, then the value of 2cot th...

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