81 genotypes in a hybrid selfing will produces how many phenotypes ?

Options

A. 81
B. 16
C. 8
D. 32

Answer

To solve the question of how many phenotypes will be produced from 81 genotypes in a hybrid selfing, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Relationship Between Genotypes and Phenotypes**:
- In genetics, the number of phenotypes can be calculated from the number of genotypes using specific formulas. The formula for the number of genotypes (G) is \(3^n\) and for the number of phenotypes (P) is \(2^n\), where \(n\) is the number of heterozygous loci.

2. **Identify the Given Information**:
- We are given that there are 81 genotypes. Therefore, we can set up the equation based on the genotype formula:
\[ 3^n = 81 \]

3. **Solve for \(n\)**:
- To find \(n\), we need to express 81 as a power of 3:
\[ 81 = 3^4 \]
- Thus, we can equate:
\[ 3^n = 3^4 \implies n = 4 \]

4. **Calculate the Number of Phenotypes**:
- Now that we have \(n = 4\), we can use the phenotype formula:
\[ P = 2^n = 2^4 \]
- Calculating this gives:
\[ P = 16 \]

5. **Conclusion**:
- Therefore, the number of phenotypes produced from 81 genotypes in a hybrid selfing is **16**.

### Final Answer:
The correct answer is **16**.

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