Red eyed female Drosophila is crossed with white eyed male. If this cross results in 50% progeny being red eyed, we can say that -

Options

A. Both parents were hemizygous
B. Female parent was heterozygous
C. Female parent was pure
D. Both parents were pure

Answer

To solve the problem, let's break it down step by step:

### Step 1: Identify the traits of the parents
- The red-eyed female Drosophila is the dominant trait (let's denote it as "R").
- The white-eyed male Drosophila is the recessive trait (denote it as "r").

### Step 2: Determine the genotypes of the parents
- The female can be either homozygous dominant (RR) or heterozygous (Rr).
- The male must be homozygous recessive (rr) since he has white eyes.

### Step 3: Analyze the possible crosses
1. **If the female is homozygous (RR)**:
- Cross: RR (female) x rr (male)
- Progeny: All offspring would be Rr (red-eyed).
- Result: 100% red-eyed progeny.

2. **If the female is heterozygous (Rr)**:
- Cross: Rr (female) x rr (male)
- Progeny: 50% Rr (red-eyed) and 50% rr (white-eyed).
- Result: 50% red-eyed and 50% white-eyed progeny.

### Step 4: Interpret the results
- Since the problem states that 50% of the progeny are red-eyed, it indicates that the female parent must be heterozygous (Rr) and the male is homozygous recessive (rr).

### Conclusion
From the analysis, we conclude that the correct answer is:
- **The female parent is heterozygous.**

### Final Answer
**B. The female parent was heterozygous.**

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