What will be the percentage inheritance of a disorder from an X-linked diseased father to his son.

Options

A. 0
B. 0.25
C. 0.5
D. 1

Answer

To determine the percentage inheritance of an X-linked disorder from an X-linked diseased father to his son, follow these steps:

### Step-by-Step Solution:

1. **Understand X-linked Inheritance**:
- X-linked disorders are caused by mutations in genes located on the X chromosome. Males have one X and one Y chromosome (XY), while females have two X chromosomes (XX).

2. **Genotype of the Diseased Father**:
- Since the father has an X-linked disorder, his genotype will be represented as X^dY, where X^d indicates the X chromosome carrying the disorder.

3. **Genotype of the Normal Mother**:
- If the mother is normal, her genotype will be XX, meaning she has two normal X chromosomes.

4. **Gametes Produced**:
- The father can produce two types of gametes: X^d (with the disorder) and Y (without the disorder).
- The mother can produce only one type of gamete: X (normal).

5. **Possible Offspring Genotypes**:
- When we combine the gametes from both parents, we can get the following combinations:
- From X^d (father) and X (mother): X^dX (daughter with the disorder)
- From Y (father) and X (mother): XY (son, normal)

6. **Inheritance to the Son**:
- Since the son inherits the Y chromosome from his father and the X chromosome from his mother, he will not inherit the X-linked disorder. Therefore, the son will have the genotype XY (normal).

7. **Percentage of Inheritance**:
- Since the son cannot inherit the X-linked disorder from his father, the percentage of inheritance of the disorder from an X-linked diseased father to his son is 0%.

### Final Answer:
The percentage inheritance of the disorder from an X-linked diseased father to his son is **0%**.

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