If a colourblind female marries a normal male (XY) then :-

Options

A. All the sons are normal
B. All the sons are colourblind
C. All the daughter are colourblind
D. Both sons and daughters are colourblind

Answer

To solve the question regarding the offspring of a colorblind female and a normal male, we will follow these steps:

### Step 1: Understand the Genetics of Colorblindness
Colorblindness is a sex-linked recessive trait, which means it is carried on the X chromosome. A colorblind female has two copies of the colorblind allele (XcXc), while a normal male has one normal allele (XY).

### Step 2: Determine the Genotypes of the Parents
- The colorblind female's genotype: XcXc (where Xc represents the colorblind allele).
- The normal male's genotype: XY (where X represents the normal vision allele).

### Step 3: Determine the Gametes Produced by Each Parent
- The colorblind female can only produce Xc gametes.
- The normal male can produce X and Y gametes.

### Step 4: Set Up a Punnett Square
To visualize the potential offspring, we can set up a Punnett square:

| | X (from male) | Y (from male) |
|---------|----------------|----------------|
| Xc (from female) | XcX (carrier daughter) | XcY (colorblind son) |
| Xc (from female) | XcX (carrier daughter) | XcY (colorblind son) |

### Step 5: Analyze the Results
From the Punnett square, we can see:
- 50% of the offspring will be carrier daughters (XcX).
- 50% of the offspring will be colorblind sons (XcY).

### Conclusion
Thus, the answer to the question is that all sons will be colorblind (XcY).

### Final Answer
**All sons are colorblind.**

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