Home
Class 12
PHYSICS
Find the moment of inertia of a disk abo...

Find the moment of inertia of a disk about an axis passing through a point on its circumference perpendicular to its plane.

Text Solution

Verified by Experts

The correct Answer is:
`3/2MR^2`
Promotional Banner

Similar Questions

Explore conceptually related problems

A uniform disc of mass 5 kg has a radius of 0.5 m. Its moment of inertia about an axis passing through a point on its circumference and perpendicular to its plane is

The moment of inertia of a copper disc, rotating about an axis passing through its centre and perpendicular to its plane

The moment of inertia of a then circular disc about an axis passing through its centre and perpendicular to its plane is I . Then, the moment of inertia of the disc about an axis parallel to its diameter and touching the edge of the rim is

The moment of inertia of ring about an axis passing through its diameter is I . Then moment of inertia of that ring about an axis passing through its centre and perpendicular to its plane is

The Moment of inertia of a disc about an axis passing through its centre and perpendicular to its plane is 1 / 2 MR^2 . Derive the values of moment of inertia of the disc about its diameter and about an axis tangential to the disc lying on its plane ?

The moment of inertia of a circular disc about an axis passing through the circumstances perpendicular to the plane of the disc is

The moment of inertia of a uniform ring about an axis passing through its centre and perpendicular to its plane is 100kgm^(2) . What is the moment of inertia of the ring about its diameter ?

The moment of inertia of a circular disc about an axis passing through its centre and perpendicular to the plane is 4 kg m^(2) . Its moment of inertia about the diameter is

The moment of inertia of an thin circular disc about an axis passing through its center and perpendicualr to its plane, is l. Then, the moment of intertia of the disc about an axis parallel to its diameter and touching the edge of the rim is

Derive an expression for moment of inertia of a thin circular ring about an axis passing through its centre and perpendicular to the plane of the ring.