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A solid flywheel of 20 kg mass and 120 m...

A solid flywheel of 20 kg mass and 120 mm radius revolves at 600 r.p.m. With what force must a brake lining be pressed against it for the flywheel to stop in 3 s, if the coefficient of friction is 0.1?

Text Solution

Verified by Experts

The correct Answer is:
`2.5 xx10^2N`

The work of the force of friction is responsible for the loss of the entire kinetic energy of the flywheel. We have
`DeltaK = (Iomega^2)/2=(mr^2omega^2)/4, W_r=Tl=muNv_(av)t=(muNomegart)/2`
Hence
`N = (mromega)/(2mut)=(pi m rn)/(mut)`
Try to solve this problem with the aid of the fundamental equation of rotational dynamics of a rigid body.
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