For an equilateral prism `angleA + anglei= anglee + angleD `

For a prism angleA + angleD= anglei + anglee = _______

Find angleA+angleB+angleC+angleD

Find the angle of minimum deviation for an equilateral prism made of a material of refractive index 1.732. What is the angle of incidence for this deviation ?

A beam of monochromatic light is incident at i= 50^(@) on one face of an equilateral prism, the angle of emergence is 40^(@) , then the angle of minimum deviation is :

Write a relation for the angle of deviation (delta) for a ray of light passing through an equilateral prism in terms of the angle of incidence (i_(1)) , angle of emergence (i_(2)) ang angle of prism (A).

Angle of minimum deviation is equal to the angle prism A of an equilateral glass prism. The angle incidence at which minimum deviation will be obtained is

Draw a neat diagram for the passage of a ray of light through an equilateral glass prism, showing clearly (a) angle of incidence (b) angle of emergence ( c ) angle of deviation (d) angle of prism

A ray of light is incident normally on one face of an equilateral prism of refractive index 1.5 . The angle of deviation is: (Given sin^-1.(2)/(3)=42^@ )

If the angle of minimum deviation is of 60^@ for an equilateral prism , then the refractive index of the material of the prism is

A ray of light passes through an equilateral glass prism in such a manner that the angle of incidence is equal to the angle of emergence and each of these angles is equal to 3/4 of the angle of the prism. The angle of deviation is