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The shoe sizes of 30 players selected fo...

The shoe sizes of 30 players selected for interschool competitions are given below :
`{:("Shoe size"(x_(i)),7,10,9,8,5,11,6),("Number of players"(f_(i)),4,5,8,3,5,2,3):}`
Find the median of this frequency distribution.

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The correct Answer is:
To find the median of the given frequency distribution, we will follow these steps: ### Step 1: Organize the Data First, we will organize the shoe sizes and their corresponding frequencies into a tabular form. | Shoe Size (x_i) | Frequency (f_i) | |------------------|-----------------| | 5 | 4 | | 6 | 5 | | 7 | 8 | | 8 | 3 | | 9 | 5 | | 10 | 2 | | 11 | 3 | ### Step 2: Calculate the Total Frequency (N) Next, we need to calculate the total number of players (N) by summing up the frequencies. \[ N = 4 + 5 + 8 + 3 + 5 + 2 + 3 = 30 \] ### Step 3: Calculate the Cumulative Frequency Now, we will calculate the cumulative frequency (CF) for each shoe size. | Shoe Size (x_i) | Frequency (f_i) | Cumulative Frequency (CF) | |------------------|-----------------|---------------------------| | 5 | 4 | 4 | | 6 | 5 | 4 + 5 = 9 | | 7 | 8 | 9 + 8 = 17 | | 8 | 3 | 17 + 3 = 20 | | 9 | 5 | 20 + 5 = 25 | | 10 | 2 | 25 + 2 = 27 | | 11 | 3 | 27 + 3 = 30 | ### Step 4: Find the Median Position The formula for finding the median position in a frequency distribution is: \[ \text{Median Position} = \frac{N + 1}{2} \] Substituting the value of N: \[ \text{Median Position} = \frac{30 + 1}{2} = \frac{31}{2} = 15.5 \] ### Step 5: Locate the Median Now, we will determine which cumulative frequency covers the median position of 15.5. From the cumulative frequency table, we see: - CF for shoe size 7 is 17 (covers 15.5) - CF for shoe size 6 is 9 (does not cover 15.5) Thus, the median shoe size corresponds to the shoe size where the cumulative frequency first exceeds 15.5, which is 7. ### Conclusion The median shoe size of the players is **7**. ---
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