Evaluate the
`9.01 xx2.5xx1.6`

Answer

To evaluate the expression \(9.01 \times 2.5 \times 1.6\), we will follow these steps:

### Step 1: Multiply the first two numbers
First, we will multiply \(9.01\) and \(2.5\).

1. **Multiply without decimals**:
- \(9.01\) can be treated as \(901\) (removing the decimal temporarily).
- \(2.5\) can be treated as \(25\) (removing the decimal temporarily).
- Now we perform the multiplication:
\[ 901 \times 25 \]

2. **Perform the multiplication**:
- \(901 \times 25\):
- \(901 \times 5 = 4505\)
- \(901 \times 20 = 18020\) (since \(20\) is \(2\) times \(10\))
- Now, add these two results:
\[ 4505 + 18020 = 22525 \]

3. **Adjust for decimals**:
- In \(9.01\), there are 2 decimal places.
- In \(2.5\), there is 1 decimal place.
- Total decimal places = \(2 + 1 = 3\).
- Therefore, we place the decimal point in \(22525\) to get \(22.525\).

### Step 2: Multiply the result with the third number
Now, we will multiply \(22.525\) by \(1.6\).

1. **Multiply without decimals**:
- Treat \(22.525\) as \(22525\) and \(1.6\) as \(16\).
- Now we perform the multiplication:
\[ 22525 \times 16 \]

2. **Perform the multiplication**:
- \(22525 \times 16\):
- \(22525 \times 6 = 135150\)
- \(22525 \times 10 = 225250\) (since \(10\) is \(1\) times \(10\))
- Now, add these two results:
\[ 135150 + 225250 = 360400 \]

3. **Adjust for decimals**:
- In \(22.525\), there are 3 decimal places.
- In \(1.6\), there is 1 decimal place.
- Total decimal places = \(3 + 1 = 4\).
- Therefore, we place the decimal point in \(360400\) to get \(36.0400\), which simplifies to \(36.04\).

### Final Answer
Thus, the result of \(9.01 \times 2.5 \times 1.6\) is:
\[ \boxed{36.04} \]