Subtract: `36^(@)53'` from `71^(@) 34'`

Answer

To solve the problem of subtracting `36° 53'` from `71° 34'`, we can follow these steps:

### Step 1: Write down the values
We have:
- Minuend (the number from which we are subtracting): `71° 34'`
- Subtrahend (the number we are subtracting): `36° 53'`

### Step 2: Check the minutes
Since we are subtracting `53'` from `34'`, we notice that `34'` is less than `53'`. This means we cannot directly subtract the minutes.

### Step 3: Borrow 1 degree
To solve this, we need to borrow 1 degree from the degrees in `71°`. When we borrow 1 degree, we convert it into minutes:
- 1 degree = 60 minutes
- So, we add `60'` to `34'`:
\[ 34' + 60' = 94' \]
- Now, we have `70°` left (since we borrowed 1 degree from `71°`).

### Step 4: Rewrite the values
After borrowing, we rewrite the values:
- New minuend: `70° 94'`
- Subtrahend remains the same: `36° 53'`

### Step 5: Subtract the minutes
Now we can subtract the minutes:
\[ 94' - 53' = 41' \]

### Step 6: Subtract the degrees
Next, we subtract the degrees:
\[ 70° - 36° = 34° \]

### Step 7: Combine the results
Now, we combine the results of degrees and minutes:
\[ 34° 41' \]

### Final Answer
Thus, the result of subtracting `36° 53'` from `71° 34'` is:
\[ 34° 41' \]

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