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Subtract: 35^(@) 40' from 60^(@)...

Subtract: `35^(@) 40'` from `60^(@)`

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To solve the problem of subtracting \( 35^\circ 40' \) from \( 60^\circ \), we will follow these steps: ### Step 1: Write the angles clearly We have: - \( 60^\circ \) (which can be written as \( 60^\circ 0' \)) - \( 35^\circ 40' \) ### Step 2: Prepare for subtraction We need to subtract \( 35^\circ 40' \) from \( 60^\circ 0' \). Since we cannot subtract 40 minutes from 0 minutes directly, we will need to borrow 1 degree from the 60 degrees. ### Step 3: Borrow 1 degree When we borrow 1 degree from \( 60^\circ \), it becomes \( 59^\circ \), and we convert that 1 degree into minutes. Since 1 degree is equal to 60 minutes, we add these 60 minutes to the 0 minutes we already have: - New angle: \( 59^\circ 60' \) ### Step 4: Perform the subtraction Now we can subtract: - Degrees: \( 59^\circ - 35^\circ = 24^\circ \) - Minutes: \( 60' - 40' = 20' \) ### Step 5: Combine the results Combining the results from the subtraction: - Final result: \( 24^\circ 20' \) Thus, the answer to the subtraction \( 60^\circ - 35^\circ 40' \) is \( 24^\circ 20' \). ---
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