Subtract: `58^(@) 12' 47''` from `85^(@)29' 11''`

Answer

To subtract `58° 12' 47''` from `85° 29' 11''`, we need to follow these steps:

### Step 1: Write down the values
We have:
- First value: `85° 29' 11''`
- Second value: `58° 12' 47''`

### Step 2: Align the values for subtraction
We will align the degrees, minutes, and seconds for easier subtraction:

```
85° 29' 11''
- 58° 12' 47''
```

### Step 3: Start with seconds
We need to subtract the seconds first:
- Seconds: `11'' - 47''`

Since `11''` is less than `47''`, we need to borrow 1 minute (which is 60 seconds).

- Borrow 1 minute from `29'`:
- `29'` becomes `28'`
- `11''` becomes `11 + 60 = 71''`

Now we can subtract:
- `71'' - 47'' = 24''`

### Step 4: Move to minutes
Now we subtract the minutes:
- Minutes: `28' - 12'`

Subtracting gives us:
- `28' - 12' = 16'`

### Step 5: Move to degrees
Now we subtract the degrees:
- Degrees: `85° - 58°`

Subtracting gives us:
- `85° - 58° = 27°`

### Step 6: Combine the results
Now we combine the results of our subtraction:
- The final result is `27° 16' 24''`

### Final Answer:
The result of subtracting `58° 12' 47''` from `85° 29' 11''` is:
**`27° 16' 24''`**

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