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Find dy/dx if y=4x-x^3...

Find `dy/dx if y=4x-x^3`

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To find \(\frac{dy}{dx}\) for the function \(y = 4x - x^3\), we will use the rules of differentiation. Let's go through the steps one by one. ### Step 1: Identify the function We start with the function: \[ y = 4x - x^3 \] ### Step 2: Differentiate each term We will differentiate each term of the function separately. 1. **Differentiate \(4x\)**: - The derivative of \(4x\) with respect to \(x\) is simply \(4\) because the derivative of \(x\) is \(1\) and \(4\) is a constant. 2. **Differentiate \(-x^3\)**: - Using the power rule for differentiation, which states that if \(y = x^n\), then \(\frac{dy}{dx} = nx^{n-1}\). - Here, \(n = 3\), so the derivative of \(-x^3\) is \(-3x^{3-1} = -3x^2\). ### Step 3: Combine the derivatives Now, we combine the derivatives of both terms: \[ \frac{dy}{dx} = 4 - 3x^2 \] ### Final Answer Thus, the derivative \(\frac{dy}{dx}\) is: \[ \frac{dy}{dx} = 4 - 3x^2 \] ---
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