M'- is an element above Zn in the activity series of metals. Select the correct answer in each case from (i) to (iii)
M reacts with conc. `H_2 SO_4` - to liberate hydrogen/sulphur dioxide gas.

M'- is an element above Zn in the activity series of metals. Select the correct answer in each case from (i) to (iii) M^(3+) to M :The cation gets reduced/ oxidised to neutral atom.

M'- is an element above Zn in the activity series of metals. Select the correct answer in each case from (i) to (iii) M-3e^(-) to M^(3+) : The process takes place by oxidation/reduction.

M'- is an element above Zn in the activity series of metals. State why conventional reducing agents cannot reduce the oxide of M to metal.

Correct the following statements : Conc. H_2 SO_4 reacts with zinc to liberate hydrogen.

Correct the statements Conc. H_2SO_4 reacts with zinc to liberate hydrogen.

Give a reason why metals are arranged in a series called - activity series of metals. Name a metal which reacts with c) Steam - to liberate hydrogen in each case.

With reference to the equation Cl_(2)+H_(2)Sto2HCl+S pertaining to a redox reaction - select the correct answer in each case a. Chlorine is oxidised/reduced to HCl. B. Hydrogen sulphide is oxidised /reduced to sulphur since the reaction involves addition/ removal of hydrogen. c. Chlorine acts as an oxidising / reducing agent.

What property of conc. H_2SO_4 is made use of in each of the following cases ? Give an equation for the reaction in each case : (a) hydrogen sulphide gas is passed through concentrated sulphuric acid.

Give reasons : Hydrogen is not prepared by reacting conc H_(2)SO_(4) with Zn

What is the product formed in each case when following compounds react with conc. H_(2)SO_(4) ? (i) KCl (ii) KBr (iii) NH_(3) (iv)PCl_(5)