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Factorise (a-2b)^3+(2b-3c)^3+(3c-a)^3...

Factorise `(a-2b)^3+(2b-3c)^3+(3c-a)^3`

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(a) If x + y + z=0, show that x ^(3) + y ^(3) + z ^(3)= 3 xyz. (b) Show that (a-b) ^(3) + (b-c) ^(3) + (c-a)^(3) =3 (a-b) (b-c) (c-a)

Factorise : 15 a^3 b - 35a b^3

Show that (a-b)^3+(b-c)^3+(c-a)^3=3(a-b)(b-c)(c-a)

Factorise : 15a^3b - 35ab^3 .

Factorise : 27a^3 + 64b^3 .

Factorise : 3ab +3a + 2b + 2.

Factorise a ^(3) - 3a^(2) b + 3ab ^(2) -b ^(3)

If a +b +c=6 , then the value of (2-a) ^3+(2-b) ^3+(2-c) ^3- 3(2-a) (2-b) (2-c) is

|(3, a+b+c, a^(2)+b^(2)+c^(2)),(a+b+c, a^(2)+b^(2)+c^(2), a^(3)+b^(3)+c^(3)), (a^(2)+b^(2)+c^(2),a^(3)+b^(3)+c^(3), a^(4)+b^(4) +c^(4))| =K(a-b)^(2)(b-c)^(2)(c-a)^(2) then k =

Factorise 27a^3+b^3+8c^3-18abc using identity