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The value of tan840^(@) is equal to...

The value of `tan840^(@)` is equal to

A

`(1)/(sqrt(3))`

B

`-(1)/(sqrt(3))`

C

`sqrt(3)`

D

`-sqrt(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( \tan 840^\circ \), we can follow these steps: ### Step 1: Reduce the angle First, we note that the tangent function has a periodicity of \( 180^\circ \). This means: \[ \tan(θ) = \tan(θ + n \cdot 180^\circ) \] for any integer \( n \). To reduce \( 840^\circ \), we can subtract \( 720^\circ \) (which is \( 4 \times 180^\circ \)): \[ 840^\circ - 720^\circ = 120^\circ \] Thus, we have: \[ \tan(840^\circ) = \tan(120^\circ) \] ### Step 2: Find \( \tan 120^\circ \) Next, we need to find \( \tan 120^\circ \). We know that: \[ 120^\circ = 180^\circ - 60^\circ \] Using the tangent subtraction identity: \[ \tan(180^\circ - θ) = -\tan(θ) \] we can write: \[ \tan(120^\circ) = -\tan(60^\circ) \] ### Step 3: Calculate \( \tan 60^\circ \) We know that: \[ \tan(60^\circ) = \sqrt{3} \] Therefore: \[ \tan(120^\circ) = -\tan(60^\circ) = -\sqrt{3} \] ### Step 4: Final Result Thus, we find: \[ \tan(840^\circ) = \tan(120^\circ) = -\sqrt{3} \] ### Conclusion The value of \( \tan 840^\circ \) is: \[ -\sqrt{3} \approx -1.732 \] ---
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