In a `DeltaABC`, show that `sum(b+c)cosA=2s`, where `s=(a+b+c)/(2)`

In any DeltaABC, sum (b - c) cot A/2 =

Statement I If the sides of a triangle are 13, 14 15 then the radius of in circle =4 Statement II In a DeltaABC, Delta = sqrt(s (s-a) (s-b) (s-c)) where s=(a+b+c)/(2) and r =(Delta)/(s)

In a DeltaABC , sum (b + c) cos A=

In any DeltaABC , prove that (a+b-c) cot (B/2) = (a-b+c) cot (C/2)

In any DeltaABC , prove that ac""cosB-bc""cosA=a^(2)-b^(2)

In DeltaABC , prove that: (b-c)/acos^(2)A/2+(c-a)/(b)cos^(2)B/2+(a-b)/(c ).cos^(2)C/2=0

In any Delta A B C , prove that: 2(bc cosA+cacosB+a bcosC)=a^2+b^2+c^2

In DeltaABC , prove that: (b-c)^(2)cos^(2)A/2+(b+c)^(2)sin^(2)A/2=a^(2)

In DeltaABC , prove that: (c-bcosA)/(b-c (cosA))=(cosB)/(cosC)

In any DeltaABC,sum(cosA)/(bcosC+ c cosB) is equal to