Home
Class 11
MATHS
Equation of the parabola with focus (0,-...

Equation of the parabola with focus `(0,-3)` and the directrix `y=3` is: (a)`x^(2)=-12y` (b)`x^(2)=12y` (c)`x^(2)=3y` (d)`x^(2)=-3y`

A

`x^(2)=-12y`

B

`x^(2)=12y`

C

`x^(2)=3y`

D

`x^(2)=-3y`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • MODEL TEST PAPER-2

    ICSE|Exercise Section-C|10 Videos
  • MODEL TEST PAPER-2

    ICSE|Exercise Section-C|10 Videos
  • MODEL TEST PAPER-19

    ICSE|Exercise SECTION - C |10 Videos
  • MODEL TEST PAPER-6

    ICSE|Exercise SECTION - C|10 Videos

Similar Questions

Explore conceptually related problems

The equation of the parabola with focus (1,-1) and directrix x + y + 3 = 0, is

The equation of axis of the parabola having focus (2,3) and directrix x-4y+3=0 is

Find the equation of the parabola whose focus is (2, 3) and directrix is x-2y-6=0 .

Find the equation of the parabola having focus at(-1,-2) and directrix is x – 2y+3=0.

Find the equation of the parabola whose focus is at (-1,-2) and the directrix the line x-2y+3=0

Find the equation of the parabola whose focus is at (-1,-2) and the directrix the line x-2y+3=0

Find the equation to the parabola whose focus is (-2,1) and directrix is 6x-3y=8 .

The equation of the parabola whose focus is (1,-1) and the directrix is x+y+7=0 is (a) x^2+y^2-2x y-18 x-10 y=0 (b) x^2+y^2-18 x-10 y-45=0 (c) x^2-18 x-10 y-45=0 (d) x^2+y^2-2x y-18 x-10 y-45=0

The equation of the parabola with focus (0,0) and directrix x+y=4 is a. x^2+y^2-2x y+8x+8y-16=0 b. x^2+y^2+8x+8y-16=0 c. x^2+y^2-2x y+8x+8y=0 d. x^2-y^2+8x+8y-16=0

Equation of directrix of the parabola 3x^(2) = 8y is