To solve the problem of finding the probability that a four-digit number formed from the digits 0, 2, 3, and 5 is divisible by 5, we can follow these steps:
### Step 1: Determine the Total Number of Four-Digit Numbers
To form a four-digit number using the digits 0, 2, 3, and 5 without repetition, we need to ensure that the first digit is not 0 (as it would then be a three-digit number).
1. **Choose the first digit**: It can be either 2, 3, or 5 (3 options).
2. **Choose the second digit**: After choosing the first digit, we have 3 digits left (including 0), so we have 3 options.
3. **Choose the third digit**: After choosing the first and second digits, we have 2 digits left, so we have 2 options.
4. **Choose the fourth digit**: After choosing the first three digits, we have 1 digit left, so we have 1 option.
Thus, the total number of four-digit numbers is:
\[
\text{Total Numbers} = 3 \times 3 \times 2 \times 1 = 18
\]
### Step 2: Determine the Number of Favorable Outcomes (Divisible by 5)
A number is divisible by 5 if it ends in either 0 or 5. We will consider both cases separately.
#### Case 1: Last Digit is 0
- The first digit can be either 2, 3, or 5 (3 options).
- The second digit can be filled with the remaining 2 digits (2 options).
- The third digit can be filled with the last remaining digit (1 option).
Thus, the total for this case is:
\[
\text{Case 1 Total} = 3 \times 2 \times 1 = 6
\]
#### Case 2: Last Digit is 5
- The first digit can only be 2 or 3 (2 options), since it cannot be 0.
- The second digit can be filled with the remaining 2 digits (including 0) (2 options).
- The third digit can be filled with the last remaining digit (1 option).
Thus, the total for this case is:
\[
\text{Case 2 Total} = 2 \times 2 \times 1 = 4
\]
### Step 3: Calculate the Total Favorable Outcomes
Now, we add the totals from both cases:
\[
\text{Total Favorable Outcomes} = 6 + 4 = 10
\]
### Step 4: Calculate the Probability
The probability \( P \) that a randomly formed four-digit number is divisible by 5 is given by the ratio of the number of favorable outcomes to the total number of outcomes:
\[
P = \frac{\text{Total Favorable Outcomes}}{\text{Total Numbers}} = \frac{10}{18} = \frac{5}{9}
\]
### Final Answer
Thus, the probability that a four-digit number formed from the digits 0, 2, 3, and 5 is divisible by 5 is:
\[
\frac{5}{9}
\]