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(d)/(dx)(e^((1)/(2)log(1+tan^(2)x))) is ...

`(d)/(dx)(e^((1)/(2)log(1+tan^(2)x)))` is equal to

A

`1/2sec^2x`

B

`sec^2x`

C

`secx.tanx`

D

`e^(1/2log(1+tan^2x)`

Text Solution

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The correct Answer is:
To solve the problem \(\frac{d}{dx}\left(e^{\frac{1}{2}\log(1+\tan^2 x)}\right)\), we will follow these steps: ### Step 1: Simplify the expression inside the derivative We start with the expression: \[ e^{\frac{1}{2}\log(1+\tan^2 x)} \] Using the property of logarithms, we can rewrite this as: \[ e^{\log((1+\tan^2 x)^{\frac{1}{2}})} \] This simplifies to: \[ (1+\tan^2 x)^{\frac{1}{2}} \] ### Step 2: Recognize the identity We know from trigonometric identities that: \[ 1 + \tan^2 x = \sec^2 x \] Thus, we can rewrite our expression as: \[ \sqrt{1+\tan^2 x} = \sqrt{\sec^2 x} = \sec x \] ### Step 3: Differentiate the simplified expression Now we need to differentiate \(\sec x\): \[ \frac{d}{dx}(\sec x) \] The derivative of \(\sec x\) is given by: \[ \sec x \tan x \] ### Final Answer Putting it all together, we have: \[ \frac{d}{dx}\left(e^{\frac{1}{2}\log(1+\tan^2 x)}\right) = \sec x \tan x \]
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