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Treating x as dependent variable, find t...

Treating x as dependent variable, find the line of best fit for the following data :
`{:(x, 15, 12, 11, 14, 13),(y, 26, 28, 24, 22, 30):}`
Hence, predict the value of y when x = 10

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To find the line of best fit treating \( x \) as the dependent variable, we will follow these steps: ### Step 1: Organize the Data We have the following data points: - \( x = [15, 12, 11, 14, 13] \) - \( y = [26, 28, 24, 22, 30] \) ### Step 2: Calculate the Summations Calculate the summation of \( x \) and \( y \): \[ \sum x = 15 + 12 + 11 + 14 + 13 = 65 \] \[ \sum y = 26 + 28 + 24 + 22 + 30 = 130 \] ### Step 3: Calculate the Means Calculate the means \( \bar{x} \) and \( \bar{y} \): \[ \bar{x} = \frac{\sum x}{n} = \frac{65}{5} = 13 \] \[ \bar{y} = \frac{\sum y}{n} = \frac{130}{5} = 26 \] ### Step 4: Calculate Deviations and Their Squares Now, we calculate \( x - \bar{x} \), \( y - \bar{y} \), \( (x - \bar{x})^2 \), and \( (y - \bar{y})^2 \): - For \( x - \bar{x} \): - \( 15 - 13 = 2 \) - \( 12 - 13 = -1 \) - \( 11 - 13 = -2 \) - \( 14 - 13 = 1 \) - \( 13 - 13 = 0 \) - For \( y - \bar{y} \): - \( 26 - 26 = 0 \) - \( 28 - 26 = 2 \) - \( 24 - 26 = -2 \) - \( 22 - 26 = -4 \) - \( 30 - 26 = 4 \) - Now calculate \( (x - \bar{x})^2 \) and \( (y - \bar{y})^2 \): - \( (2)^2 = 4 \) - \( (-1)^2 = 1 \) - \( (-2)^2 = 4 \) - \( (1)^2 = 1 \) - \( (0)^2 = 0 \) ### Step 5: Calculate Summations of Squares and Products Now we calculate: \[ \sum (x - \bar{x})^2 = 4 + 1 + 4 + 1 + 0 = 10 \] \[ \sum (y - \bar{y})^2 = 0 + 4 + 4 + 16 + 16 = 40 \] \[ \sum (x - \bar{x})(y - \bar{y}) = (2)(0) + (-1)(2) + (-2)(-2) + (1)(-4) + (0)(4) = 0 - 2 + 4 - 4 + 0 = -2 \] ### Step 6: Calculate the Slope \( b_{xy} \) Now we can calculate the slope \( b_{xy} \): \[ b_{xy} = \frac{\sum (x - \bar{x})(y - \bar{y})}{\sum (y - \bar{y})^2} = \frac{-2}{40} = -0.05 \] ### Step 7: Write the Regression Equation The regression equation of \( x \) on \( y \) is given by: \[ x - \bar{x} = b_{xy}(y - \bar{y}) \] Substituting the values: \[ x - 13 = -0.05(y - 26) \] Rearranging gives: \[ x = -0.05y + 13 + 1.3 \] \[ x = -0.05y + 14.3 \] ### Step 8: Predict \( y \) when \( x = 10 \) Now, we need to predict the value of \( y \) when \( x = 10 \): \[ 10 = -0.05y + 14.3 \] Rearranging gives: \[ -0.05y = 10 - 14.3 \] \[ -0.05y = -4.3 \] Dividing by -0.05: \[ y = \frac{-4.3}{-0.05} = 86 \] ### Final Answer The predicted value of \( y \) when \( x = 10 \) is \( y = 86 \). ---
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