Home
Class 12
MATHS
Area of the regionbounded by the curve y...

Area of the regionbounded by the curve `y = "cos" x` between `x = 0` and `x = pi` is

Text Solution

Verified by Experts

The correct Answer is:
a
Promotional Banner

Topper's Solved these Questions

  • MODEL TEST PAPER - 10

    ICSE|Exercise SECTION - C|10 Videos
  • MODEL TEST PAPER - 10

    ICSE|Exercise SECTION - C|10 Videos
  • MOCK TEST PAPER -2021

    ICSE|Exercise SECTION -C (15 MARKS )|10 Videos
  • MODEL TEST PAPER - 13

    ICSE|Exercise SECTION - C(15 MARKS)|10 Videos

Similar Questions

Explore conceptually related problems

Find the area of the region bounded by the curve y = sin x between x = 0 and x= 2pi .

Find the area bounded by the curve y = cos x between x = 0 and x=2pi .

The area of the region bounded by the curve y = "sin" x between the ordinates x=0 , x=pi/2 and the X-"axis" is

Find the area of that region bounded by the curve y="cos"x, X-axis, x=0 and x=pi .

The area of the region bounded by the curve y=x"sin"x, x-axis, x=0 and x=2pi is :

If f(x) = max {sin x, cos x,1/2}, then the area of the region bounded by the curves y =f(x), x-axis, Y-axis and x=(5pi)/3 is

Find the area of region by the curve y=sinx" between "x=0" and "x=2pi .

Statement-I: The sine and cosine curves intersect infinitely many tmes, bounding regions of equal areas. Statement-II : The area of the figure bounded by the curves y=cos x and y=sin x and the ordinates x = 0 and x=(pi)/(4) is sqrt(2)-1 sq. units. Which of the above statement is correct.

The area bounded by the curves y=cosx and y=sinx between the ordinates x=0 and x=(3pi)/2 is

The ratio of the areas bounded by y=cosx,y=cos2x between x=0 and x=pi//3 and the x-axis is