Write as a single matrix: `((-1,2,3))((-2,-1,5),(0,-1,4),(7,0,5))-2((4,-5,-7))`

Answer

To solve the problem, we will follow these steps:

### Step 1: Define the matrices
Let \( A = (-1, 2, 3) \) be a row matrix and \( B = \begin{pmatrix} -2 & -1 & 5 \\ 0 & -1 & 4 \\ 7 & 0 & 5 \end{pmatrix} \) be a 3x3 matrix. We also have a row matrix \( C = (4, -5, -7) \).

### Step 2: Multiply matrix A with matrix B
To find the product \( A \times B \), we compute the following:

\[ A \times B = (-1, 2, 3) \begin{pmatrix} -2 & -1 & 5 \\ 0 & -1 & 4 \\ 7 & 0 & 5 \end{pmatrix} \]

Calculating each element of the resulting matrix:

1. First column:
\[ -1 \times -2 + 2 \times 0 + 3 \times 7 = 2 + 0 + 21 = 23 \]

2. Second column:
\[ -1 \times -1 + 2 \times -1 + 3 \times 0 = 1 - 2 + 0 = -1 \]

3. Third column:
\[ -1 \times 5 + 2 \times 4 + 3 \times 5 = -5 + 8 + 15 = 18 \]

Thus, we have:
\[ A \times B = (23, -1, 18) \]

### Step 3: Multiply the result by -2 times matrix C
Now we need to compute \( -2 \times C \):
\[ -2 \times (4, -5, -7) = (-8, 10, 14) \]

### Step 4: Add the two results
Now we add the results from Step 2 and Step 3:
\[ (23, -1, 18) + (-8, 10, 14) \]

Calculating each element:
1. First element:
\[ 23 - 8 = 15 \]

2. Second element:
\[ -1 + 10 = 9 \]

3. Third element:
\[ 18 + 14 = 32 \]

Thus, the final result is:
\[ (15, 9, 32) \]

### Final Answer
The single matrix representation is:
\[ \boxed{(15, 9, 32)} \]

---