A tank full of water has a small hole at its bottom. Let `t_(1)` be the time taken to empty the first half of the tank and `t_(2)` be the time needed to empty the rest half of the tank, then

A tank full of water has a small hole at its bottom. Let t_(1) be the time taken to empty first one third of the tank and t_(2) be the time taken to empty second one third of the tank and t_(3) be the time taken to empty rest of the tank then (a). t_(1)=t_(2)=t_(3) (b). t_(1)gtt_(2)gtt_(3) (c). t_(1)ltt_(2)ltt_(3) (d). t_(1)gtt_(2)ltt_(3)

A tank is filled with a liquid upto a height H, A small hole is made at the bottom of this tank Let t_(1) be the time taken to empty first half of the tank and t_(2) time taken to empty rest half of the tank then find (t_(1))/(t_(2))

A tank full of water has a small hole at the bottom. If one-fourth of the tank is emptied in t_(1) seconds and the remaining three-fourths of the tank is emptied in t_(2) seconds. Then the ratio (t_(1))/(t_(2)) is

A tank has a hole at its bottom. The time needed to empty the tank from level h_(1) to h_(2) will be proportional to

Liquid is filled in a container upto a height of H . A small hle is made at the bottom of the tank. Time taken to empty from H to (H)/(3) is t_(0) . Find the time taken to empty tank from (H)/(3) to zero.

A cylindrical tank full of water is emptied by a pipe at the rate of 225 litres per minute. How much time will it take to empty half the tank, if the diameter of its base is 3 m and its height is 3.5 m? [Use pi=22//7 ]

A large open tank is filled with water upto a height H. A small hole is made at the base of the tank. It takes T_1 time to decrease the height of water to H/n(ngt1) and it takes T_(2) time to take out the remaining water. If T_(1)=T_(2) , then the value of n is