A square ABCD has all its vertices on the curve `x^2y^2=1`. The midpoints of its sides also lie on the same curve. Then, the square of area of ABCD is ________ .

Four points lying on the curves x^2y^2=1 form a square such that mid-points os sides also lies on the given curve. Find the square of area of the square

The area of square ABCD is 16cm^(2). Find the area of the square joining the mid-point of the sides.

If a vertex of a square is at (1,-1) and one of its side lie alongthe line 3x-4y-17=0 then find the area of the square.

If one side of the square is 2x-y+6=0 then one of the vertices is (2,1). Find the other sides of the square.

The area of a square ABCD is 36cm^(2) . Find the area of the square obtained by joining the midpoints of the sides of the square ABCD.

ABCD is a square of area 100cm^2. E,F,G,H are the mid points of its sides. K,L,M,N.are the mid points of the sides of EFGH. Find the area of KLMN.

Points X and Y are on sides BC and CD of square ABCD, as shown in the figure.The lengths of XY,AX and AY are 3,4 and 5 units respectively.Then the side length of square ABCD is: