`inte^x((1+xlogx)/x)dx`

int e^x ((1+xlogx)/x)dx=e^x (mlog x) +c , then m=

Evaluate: int(e^x(1+xlogx))/xdx

int_(1)^(e)e^(x)((1+xlogx)/(x))dx

int(e^(x)(1+xlogx))/(x)dx=

int(1)/(xlogx)dx

Evaluate each of the following integral: int_e^(e^2)1/(xlogx)dx

int x^(x) (1+ log x) dx

int(1)/(x)(1+log x)dx

The integral inte^x(f(x)+f\'(x))dx can be solved by using integration by parts such that: I=inte^xf(x)dx+inte^xf\'(x)dx=e^xf(x)-inte^xf\'(x)dx+inte^xf\'(x)dx=e^xf(x)+C , and inte^(ax)(f(x)+(f\'(x))/a)dx=e^(ax)f(x)/a+C ,Now answer the question: inte^x x^x(2+logx)= (A) e^x x^xlogx+C (B) e^x+x^x+C (C) e^x x(logx)^2+C (D) e^x.x^x+C