The kinetic energy (KR) of photoelectron emitted on irradiating a metal surface with frequency `.vartheta.` is related by `KE = h vartheta - IE`. The plots of K.E vs incident frequency is a straight line which shows

The maximu kinetic energy (E_(k)) of the photoelectron varies with frequency (v) of the incident light as shown by the curve:

Maximum kinetic energy (E_(k)) of a photoelectron varies with the frequency (v) of the incident radiation as

The kinetic energy (E_(k)) of a photoelectron varies with the frequency (v) of the incident radiation as which of the following graph ?

When a certain metal was irradiated with a light of 8.1 xx 10^(16)Hz frequency, the photoelectron emitted had 1.5 times the kinetic energy as the photoelectrons emitted when the same metal was irradiated with light 5.8 xx 10^(16)Hz frequency. If the same metal is irradiated with light of 3.846nm wave length, what will be the energy of the photoelectron emitted?

Assertion (A) : Kinetic energy of photoelectrons emitted by a photosensitive surface depends upon the frequency of incident photon. Reason (R ): The ejection of electrons from metallic surface is possible with frequency of incident photon below the threshold frequency.

The maximum velocity of the photoelectrons emitted from the surface is v when light of frequency n falls on a metal surface. If the incident frequency is increased to 3n, the maximum velocity of the ejected photoelectrons will be

The maximum velocity of the photoelectrons emitted from the surface is v when light of frequency n falls on a metal surface. If the incident frequency is increased to 3n, the maximum velocity of the ejected photoelectrons will be:

The maximum kinetic energy of photoelectrons ejected from a metal, when it is irradiated with radiation of frequency 2xx10^(14)s^(-1) is 6.63xx10^(-20) J. the threshold frequency of the metal is: