Transform the equation ` x/a + y/b = 1` into normal form when `a>0` and `b>0`. If the perpendicular distance from origin to the line is `p` then deduce that ` 1 / p^2 = 1 / a^2 + 1 / b^2`

Reduce each of the equations to the normal form and find the length of the perpendicular from origin to the line x+y-2=0

The length of perpendicular from the origin on the line x/a + y/b = 1 is -

if P is the length of perpendicular from origin to the line (x)/(a)+(y)/(b)=1 then prove that (1)/(a^(2))+(1)/(b^(2))=(1)/(p^(2))

Find the distance of the point P from the line l in that : l: x/a - y/b = 1 and P-= (b, a)

If 'p' be the measure of the perpendicular segment from the origin on the line whose intercepts on the axes are 'a' and 'b'.then prove that : (1)/(p^(2)) = (1)/(a^(2)) + (1)/(b^(2))

Consider the following statements : 1. For an equation of a line, x cos q + y sin q = p , in normal form, the length of the perpendicular from the point (a, b) to the line is |a cos q+b sin q+p| . 2. The length of the perpendicular from the point (a, b) to the line x/a+y/b=1 is |(a alpha+b beta-ab)/sqrt(a^(2)+b^(2))| . Which of the above statements is/are correct ?