Ethanol reacts with sodium and forms two products. These products are

Options

A. Sodium hydroxide and hydrogen gas
B. Sodium ethanoate and ethanoic acid
C. Sodium ethoxide and hydrogen gas
D. Sodium hydroxide and ethanoic acid

Answer

To determine the products formed when ethanol reacts with sodium, we can follow these steps:

### Step 1: Identify the Reactants
Ethanol is the reactant in this reaction. Its chemical formula is C2H5OH, which can also be written as CH3CH2OH. Sodium (Na) is the other reactant.

### Step 2: Write the Reaction
When ethanol reacts with sodium, the reaction can be represented as:
\[ \text{C}_2\text{H}_5\text{OH} + \text{Na} \rightarrow \text{Products} \]

### Step 3: Determine the Products
In this reaction, sodium reacts with the hydroxyl group (-OH) of ethanol. The products formed are:
1. Sodium ethoxide (C2H5ONa)
2. Hydrogen gas (H2)

Thus, the balanced reaction is:
\[ 2 \text{C}_2\text{H}_5\text{OH} + 2 \text{Na} \rightarrow 2 \text{C}_2\text{H}_5\text{ONa} + \text{H}_2 \]

### Step 4: Conclusion
The two products formed when ethanol reacts with sodium are sodium ethoxide (C2H5ONa) and hydrogen gas (H2).

### Final Answer:
The products are sodium ethoxide and hydrogen gas.

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