Balance the following equation by oxidation number method in acidic medium.
`Cr_(2)O_(7)^(2-)+Fe^(2+)+H^(+)toCr^(3-)+Fe^(3+)+H_(2)O`

Explanation

To balance the equation \( \text{Cr}_2\text{O}_7^{2-} + \text{Fe}^{2+} + \text{H}^+ \rightarrow \text{Cr}^{3+} + \text{Fe}^{3+} + \text{H}_2\text{O} \) using the oxidation number method in acidic medium, follow these steps:

### Step 1: Assign Oxidation Numbers
- For \( \text{Cr}_2\text{O}_7^{2-} \):
- Let the oxidation number of Cr be \( x \).
- The equation becomes \( 2x + 7(-2) = -2 \).
- Solving gives \( 2x - 14 = -2 \) → \( 2x = 12 \) → \( x = +6 \).
- Thus, the oxidation number of Cr in \( \text{Cr}_2\text{O}_7^{2-} \) is +6.
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