Balance the following equation in basic medium.
`Cr(OH)_(3)+IO_(3)^(-)toCrO_(4)^(2-)+I^(-)`

Explanation

To balance the equation \( \text{Cr(OH)}_3 + \text{IO}_3^- \rightarrow \text{CrO}_4^{2-} + \text{I}^- \) in basic medium, we will use the oxidation number method. Here are the steps:

### Step 1: Determine the oxidation states
- In \( \text{Cr(OH)}_3 \):
- Let the oxidation state of Cr be \( x \).
- The equation becomes \( x + 3(-1) = 0 \) (since OH has a -1 charge).
- Thus, \( x = +3 \).

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