Home
Class 11
CHEMISTRY
Split the following redox reactions into...

Split the following redox reactions into two half reactions :
`Zn+Fe^(2+)toZn^(2+)+Fe`

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • REDOX REACTIONS (OXIDATION AND REDUCTION)

    ICSE|Exercise VERY SHORT ANSWER TYPE QUESTIONS |27 Videos
  • REDOX REACTIONS (OXIDATION AND REDUCTION)

    ICSE|Exercise SHORT ANSWER TYPE QUESTIONS |12 Videos
  • REDOX REACTIONS (OXIDATION AND REDUCTION)

    ICSE|Exercise NCERT TEXT-BOOK. EXERCISES ((With Hints and Solutions)|69 Videos
  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    ICSE|Exercise NCERT TEXT-BOOK EXERCISES (WITH HINTS AND SOLUTIONS )|72 Videos
  • SAMPLE QUESTION PAPER

    ICSE|Exercise Question|69 Videos

Similar Questions

Explore conceptually related problems

Split the following redox reactions into two half reactions : Sn^(2+)+2Fe^(3+)toSn^(4+)+2Fe^(2+)

Divide the following redox reactions into oxidation and reduction half reactions. Zn + Cu^(2+) to Zn&(2+) + Cu

Divide the following redox reactions into oxidation and reduction half reactions. Zn + Pb^(2+) to Zn^(2+) + Pb

Divide the following redox reactions into oxidation and reduction half reactions. Cl_2 + 2Br^(-) to Br_2 + 2Cl^(-)

Write correctly balanced equaitons for the following redox reaction. Using half reaction: H_(2)S+Fe^(3+)rarrFe^(2+)+Sdarr+H^(o+)

Write the following redox reactions using half equations: 2Fe^(3+)(aq)+2I^(ө)(aq)rarrI_(2)(aq)+2Fe^(2+)(aq)

Complete the given redox reaction Zn+AgCN rarr

Identify the following reactions as either oxidation or reduction : Fe^(3+) +e^(-) to Fe^(2+)

Justify that the following reactions are redox reactions : Fe_(2)O_(3)(s)+3CO(g)to2Fe(s)+3CO_(2)(g)

Balance the following equations by ion electron (half reaction) method for each of the following equations: Cr_(2)O_(7)^(2-) + Fe^(2+) rarr cr^(3+) + Fe^(3+) + H_(2)O

ICSE-REDOX REACTIONS (OXIDATION AND REDUCTION)-REVIEW EXERCISES
  1. On the basis of the electron transfer, explain which ion is getting ox...

    Text Solution

    |

  2. On the basis of the electron transfer, explain which ion is getting ox...

    Text Solution

    |

  3. Split the following redox reactions into two half reactions : Zn+Fe^...

    Text Solution

    |

  4. Split the following redox reactions into two half reactions : Sn^(2+...

    Text Solution

    |

  5. Calculate the oxidation number of nitrogen in the following oxides. ...

    Text Solution

    |

  6. Calculate the oxidation number of carbon in the following compounds. ...

    Text Solution

    |

  7. Calculate the oxidation number of the underlined atom in the following...

    Text Solution

    |

  8. Calculate the oxidation number of the underlined atom in the following...

    Text Solution

    |

  9. Taking the example of methanol (CH(3)OH), show that the oxidation numb...

    Text Solution

    |

  10. Using the concept of oxidation number, identify the substances undergo...

    Text Solution

    |

  11. Using the concept of oxidation number, identify the substances undergo...

    Text Solution

    |

  12. Using the concept of oxidation number, identify the substances undergo...

    Text Solution

    |

  13. Identify the oxidising and reducing agents in the following reactions....

    Text Solution

    |

  14. Identify the oxidising and reducing agents in the following reactions....

    Text Solution

    |

  15. Identify the oxidising and reducing agents in the following reactions....

    Text Solution

    |

  16. Balance the following equations by oxidation number method. HNO(3)to...

    Text Solution

    |

  17. Balance the following equations by oxidation number method. KMnO(4)+...

    Text Solution

    |

  18. Balance the following equations by oxidation number method. MnO(4)^(...

    Text Solution

    |

  19. Balance the following equations by oxidation number method. MnO(2)+H...

    Text Solution

    |

  20. Balance the following equations by oxidation number method. NaOH+Cl(...

    Text Solution

    |