`E_(Li^(+)//Li)^(@)=-3.05V and `E_(Ca^(2+)//Ca)^(@)=-2.87V,` state which is a better reducing agent Li or Ca?

Explanation

To determine which element, lithium (Li) or calcium (Ca), is a better reducing agent based on their standard reduction potentials, we can follow these steps:

### Step 1: Understand the Concept of Reducing Agents
A reducing agent is a substance that donates electrons in a chemical reaction and gets oxidized in the process. The strength of a reducing agent can be inferred from its standard reduction potential (E°). A lower (more negative) E° value indicates a stronger reducing agent.

### Step 2: Identify the Given Standard Reduction Potentials
We have the following standard reduction potentials:
- For lithium: \( E^\circ (Li^+ / Li) = -3.05 \, V \)
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