Calculate the oxidation number of all the atoms in the following species.
`Sb_(2)O_(5)`

Explanation

To calculate the oxidation numbers of all the atoms in the compound \( \text{Sb}_2\text{O}_5 \), we will follow these steps:

### Step 1: Identify the elements in the compound
The compound \( \text{Sb}_2\text{O}_5 \) contains two elements: antimony (Sb) and oxygen (O).

### Step 2: Determine the oxidation number of oxygen
Oxygen typically has an oxidation number of \(-2\) in most compounds, except in peroxides, superoxides, or when bonded to more electronegative elements (like fluorine). Since there are no such conditions in \( \text{Sb}_2\text{O}_5 \), we assign oxygen an oxidation number of \(-2\).

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