The oxidation state of S in `S_(8)` is zero.

Answer

To determine the oxidation state of sulfur (S) in the molecule \( S_8 \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Molecule**:
We are given the molecule \( S_8 \), which consists of eight sulfur atoms.

2. **Recognize the Type of Species**:
The molecule \( S_8 \) is a pure element, meaning it is composed entirely of sulfur atoms.

3. **Apply the Rule for Oxidation States**:
According to the rules of oxidation states, the oxidation state of an element in its elemental form is always zero. This is because there is no difference in electronegativity between the atoms in a pure element.

4. **Conclusion**:
Since \( S_8 \) is composed solely of sulfur atoms and is in its elemental form, the oxidation state of sulfur in \( S_8 \) is 0.

5. **Final Statement**:
Therefore, the statement "The oxidation state of S in \( S_8 \) is zero" is true.